What happens if you Call a free on a pointer twice?
Suppose that you have int *a = malloc (sizeof (int)) and a has 0xdeadbeef and you execute free (a) then after execution a still contains 0xdeadbeef but after the free call this memory address is no more reserved for you.
Something like you have rented a flat with malloc used for some time, returned the flat by free then you might have a duplicate key for the flat, but it is not reserved for you.
Doing a free on an already freed memory will result in double free memory corruption.
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Answer Original Source: StackOverFlow
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