Calculate Sum Of All Numbers Present In String

Calculate sum of all numbers present in a string

sum-of-all-digits-present-in-a-string

#include <iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

int SumOfDigits(string str, int n);
int SumOfoverallNumberPresent_In_Sequence(string str, int n);

int main()
{
   char str[20];

   printf("Please enter the string:");
   gets(str);
   int length = strlen(str);
   cout<<"\n\nsum of all digits present in string is :-  "<<SumOfDigits(str, length)<<endl;
   cout<<"\n\nSum of different numbers present in string:-  "<<SumOfoverallNumberPresent_In_Sequence(str, length)<<endl;
   return 0;
  }


 int SumOfDigits(string str, int n)
 {
     int i,sum=0,num=0;
     for(i = 0;i<=n;i++)
   {
      if(str[i] >=48 && str[i] <= 57)
      {
         num = str[i]-48;
         sum = sum  + num;
      }

    }
     return sum;
 }

 int SumOfoverallNumberPresent_In_Sequence(string str, int n)
 {
    int i,sum=0,digitSum=0,Flag=0,num=0;
    for(i = 0;i<=n;i++)
    {
      if(str[i] >=48 && str[i] <= 57)
      {
         num = str[i]-48;
         sum = sum*10  + num;
      }
      else
      {
          digitSum = digitSum+sum;
          sum=0;
      }

    }
     return digitSum;
 }

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